UVaOJ 1585 – Score

问题描述

解法一：模拟

读入的时候维护表示当前 O 连续数的 cnt 变量，累加到结果 res 即可。

#include <bits/stdc++.h>

using namespace std;

int main() {
  int t;
  cin >> t;
  while (t--) {
    int res = 0, cnt = 0;
    string line;
    cin >> line;
    for (auto const &ch : line) {
      cnt = (ch == 'O') ? cnt + 1 : 0;
      res += cnt;
    }
    cout << res << endl;
  }
  return 0;
}

#include <bits/stdc++.h>

using namespace std;

int main() {

int t;

cin >> t;

while (t--) {

int res = 0, cnt = 0;

string line;

cin >> line;

for (auto const &ch : line) {

cnt = (ch == 'O') ? cnt + 1 : 0;

res += cnt;

}

cout << res << endl;

}

return 0;

}

t = int(input())
for _ in range(t):
    line = input()
    res = cnt = 0
    for ch in line:
        cnt = cnt + 1 if ch == "O" else 0
        res += cnt
    print(res)

t = int(input())

for _ in range(t):

line = input()

res = cnt = 0

for ch in line:

cnt = cnt + 1 if ch == "O" else 0

res += cnt

print(res)

AOAPC II UVaOJ 字符串

UVaOJ 1585 - Score

问题描述

解法一：模拟